day153-LeetCode 198. House Robber


You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will automatically contact the police if two adjacent houses were broken into on the same night.
Given a list of non-negative integers representing the amount of money of each house, determine the maximum amount of money you can rob tonight without alerting the police.



如果房子只有[m0], max = mo

[m0,m1], max = Max(m0,m1)

[m0,m1,m2], max = Max(m0+m2,m1)


function robber (nums) {
let maxSum = new Array()
if(nums.length === 0) return 0
if(nums.length === 1) return nums[0]
if(nums.length === 2) return Math.max(nums[1],nums[0])


for(let i = 2; i < nums.length; i++) {
// Max(m0+m2,m1),计算公式
maxSum[i] = Math.max(nums[i] + maxSum[i-2], maxSum[i-1])
return maxSum.pop()
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